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[求助]

21)n divided by 6 余 2, divided by 8 余 4, 问divided by 48 余几? 20
【确认】20

怎么做?
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all the answers are 20+24K(k=0,1,2,3,....). So some body got 20, some got44, and the original person said 68

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Ok, I give my solution.  Welcome others.

following liangqi's
  6m=8n+2
then     m=(4n+1)/3   we want to make sure m is an integre, then not every n could satisfy this eqution.
we could get m=(n+1)/3  so if we want get m is integre n should be n=3k-1
subsitutes this into x=8n+4
we get  x=24k-4
if k=2Y             x=48y-4=48y+44
if k=2Y+1         x=48y+20

So it is 2 possible numbers. every x,y k m n is integer.

Hi lianqi if you still think it not very 爽.  you can try that way like you said, just always in mind, because  6 and 8's minimal mulitiple is 24, so if divied by 48 there would be two possible values.

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I agree with kitten369.

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does any one try 44, this question should have two answers, or these numbers are not quite right

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