求助：一道数学题

longxiaomeim

A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traverling in the same direction and in the same path at a constant rate of 20 miles per hour .The cyclist stops to wait to for the hiker 5 minutes after passing her ,while the hiker continues to walk at her constant rate .How many minutes must the cyclist wait until the hiker catches up?

多谢！

jojof5460

自行车们前进的同时，hiker也在行走啊。所以是（20－4）×5是5minutes 产生的distance。clear？

longxiaomeim

能否解释一下，我每次算都是5/4。 多谢！！

hopr999

（20－4）×5/4＝20

sammen

没明白题意,好像没办法求啊?楼主这是原题,还是JJ啊?