[求助]math

jackco

G friends, please tell me how to solve "f(n)=2^x*3^y*5^z,x/y/z为n的百,十,个位，x，y，z都是正整数，f(m)=9f(v),
问m-v=?  especially the clues to solve the problem, thanks a lot!
[em27]

猫猫头

你去问ROBERT要吧，你给他发短消息，这是他管的

jackco

猫猫头,I can't get in the VIP area you said, what's wrong with me? could you tell me password? thanks a Lot!

猫猫头

在VIP会员下载讨论里有

jackco

猫猫头, thank you again, but could you tell me how to open the 9-month JJ?
I downloaded it, but I could not open it without password, where can I find the password? please help me get out of the trouble. thanks.

猫猫头

不客气，你得叫我猫猫头

jackco

小石猫, I got it, thank you very much!!

猫猫头

因为f(m)=9f(v),所以f(m)中3的次数比f(v)中多2（3^2)
所以设f(n)=2^x*3^y*5^z,f(v)=2^x'*3^y'*5^z'
coz y'-y=2===>100x+10y+z-100x'-10y'-z'=10*2(pay attention that x=x',z=z')

jackco

小石猫, please tell me again, I couldn't find the previous JJ, thank you very much. Also, could you tell me the password of  9-month JJ, I could not open it without the password. thanks again.

猫猫头

参阅前JJ，我有详细过程：P