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正态分布和百分比互求的题目怎么解答?
There are these 8 numbersin a set 9.4,9.9,9.9,9.9,10.0,10.2,10.2,10.5 The mean and standard deviation ofthe 8 numbers are 10.0 and 0.3 respectively, what percent of the 8 numbers arewithin 1 standard deviation of the mean?
a)90%
b) 85%
c) 80%
d) 75%
e) 70%
解答看懂了
但是题目其实有疑问
为什么8个数的中数是10呢
不是因为是9.9和10的平均数么?
ps
还有一道题目
The fourth grade at school X is made up of 300 students who have a total weight of 21,600 pounds.
If the weight of these four graders has a normal distribution and standard deviation equals 12 pounds, approximately what percentage of the fourth graders weighs more than 84 pounds?
a 12%
b 16%
c 36%
d 48%
e 60%
网上看了解释也看不明白
Where did you get this question? My believe is that GMAT will not be asking questions like this....
Mean = 21600/300 = 72
Mean + 1sigma (std dev) = 72 + 12 = 84
+/- 1<sigma> covers 68.2% (34.1% + 34.1%) of the normal distribution. Therefore, remain distribution of data 100% - 68.2% = 31.8%.
Since we care only about data points above 84 lbs => 31.8 / 2 = 15.9% = 16%
怎么就一下子两个sigma就得出68.2的百分比了阿?
GMAT关于正态分布到底要掌握到哪里? |
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