.DS: 45% the apartments with <=3 people living in each one. What’s the median?
(1)80% of the apartments have <=5
(2)35% of the apartments have >=5
###(C) Note: Median is 4
PG, 谢谢!
I understand it now. Becos I thought 50% is frequency.所以才搞错了。
Becos {3,3,3,(there are 45% of them), .4...} and we must look for where 50% is - correct?
谢谢PG为我解答!
But I still do not understand:
(1)Median is middle number in data set
(2)<=5, is 80%, so remainder 20% could be 6,7,8,..etc
(3)So, which is median, we cannot determine.
Pls help!
DS: 45% the apartments with <=3 people living in each one. What’s the median?
1)80% of the apartments have <=5
(2)35% of the apartments have >=5
###(C) Note: Median is 4
条件(1)- 中数可为4,5,等,
条件(2)- 从这里可以算出 15% 为5人户口.
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so far you steps are good. Next, since 15% has 5 people. combine with 1), we can get 65% has < 5. which equals to 65% <= 4;
then combine with original condition: 45% <= 3 in the statement, the median has to be 4.