老题新问GWD-8-Q41，至今没有定论：B or C

rearn

GWD-8-Q41:

When drive-ins were at the height of their popularity in the late 1950’s, some 4,000 existed in the United States, but today there are less than one-quarter that many.

 

A.      there are less than one-quarter that many

 

B.      there are fewer than one-quarter as many

 

C.      there are fewer than one-quarter of that amount

 

D.      the number is less than one-quarter the amount

 

E.       it is less than one-quarter of that amount

 

B套用了两个比较结构：fewer than, as many(as),可以吗？

 

是否可以根据amount修饰不可数排除C,D,E?

 

到底正确答案是什么？

 

grassgreen

我觉得答案是 A

GWD-8-Q41:

When drive-ins were at the height of their popularity in the late 1950’s, some 4,000 existed in the United States, but today there are less than one-quarter that many.

单独修饰分数，用less不用fewer，修饰 分数+of+n，由所修饰的n决定用less还是fewer

修饰可数名词用many，修饰不可数名词用amount。drive-ins是可数名词，所以用amount的全错，排除CDE，剩下AB。

B选项 there are fewer than one-quarter as many

as many结构错误，应该as many as，这是次要，关键在于as放在one-quarter和many之间，不能形成什么的几分之几这种结构。那么fewer应该就近修饰one-quarter，而修饰分数应该用less。

其实答案A之所以对，只要理解less than one-quarter这个结构是一个意群即可，或者理解成1/5，1/6之类的，也是一个分数，less than修饰one-quarter。1/5 that many完全可以理解成分数+of+n这个结构，由可数n决定用fewer不用less

因此这题我认为选A

liudi

关于这道题，我有2个问题。1，less是不是只可以修饰不可数，还是都可以修饰。修饰可数是不是只可以用few.

2. amount的用法，是不是可以修饰可数不可数呀啊？谢谢解答。

gifiler

新PREP2中答案是B fewer 和 as many搭配，以前也讨论过的。