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ody JJ help?
60.Bob在一个club,有两人将被选出来,问其中有Bob的概率?
(1)club 有100人
(2)如果club 少10人的话,概率为1/45
key
73,(X^4 )(Y^3) =5000, Y是多少?
1) X是整数
2)Y是正整数
==== C
。一个三位数,有两个数字重复,问有多少种可能。 3*(9*10-9)=243
。两个两位数分别为KR和MS,它们的和的十位数是M,问下面哪几种情况有可能? I)K=9 II)R+S》9 III)忘了(反正是不对的)
数学其他都比较简单,就是一定要细心,机经一定要看
群鹅,产的卵2/3孵化(be hatched),孵化的小额4/5能survive the first month, 剩下的1/3不能survive first year,问如果一年后有120只鹅,那么当初how many eggs? 600
Tax T is levied on profit P of the Nth month if P is over $5000 by the formula: T=P+N^1/2.What is the profit of September?
A. T-Sep. is over T-Apr. $4000
B. T-Sep. is over T-Jan. $2000
Answer
### x^2+3x+c=y, if y=(x+a)(x+b), ask c=? [C]
1)a=1 2)b=2
why not D?
##one unit 64% person were employed and 48% was employed male, the percentage of employed was female.
A 52% B 25%, C16%…
(64%-48%)/64%=25%
###one unit 64% person were employed and 48% was employed male, the percentage of employed was female.
A 52% B 25%, C16%…
(64%-48%)/64%=25%
###Cycle time(in days)(每次所需天数) Deliveries [29]
1 10
2 9
3 5
4 x
Average delivery cycle time is 3 days; how many delivery should there be for cycle time of 4 days
(1*10+2*9+3*5+4*X)/(10+9+5+x)=3===>X=29
###表格题
天数 传送的件数 [29]
1 10
2 9
3 5
4 X
已知每件的平均传送时间为3, 求花4天传送的件数X
题目是说, Deliveries 按5,9,10的量每三天循环一次,也就是说,第四天的x应该等于第一天的5。加起来,4天一共是29。
Still do not understand?
###f(n)为小于n并与n没有相同质因子的正整数的个数,当P为任意质数时,f(P)? [P-1]
5个数的平均数是0,其中正数的个数大于负数的个数么?
1)正数的平均数是12
2)负数的平均数是-6.( C ) |
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