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问个OG上的题,望达人指教!

An airline passenger is planning a trip that involves three connecting flights that leave from
Airports A,B, and C, respectively. The first flight leaves Airport A every hour, beginning at
8:00 a.m., and arrives at Airport B 2(1/2) hours later. The second flight leaves Airport B every
20 minutes, beginning at 8:00 a.m., and arrives at Airport C 1(1/6) hours later. The third flight
leaves Airport C every hour, beginning at 8:45 a.m. What is the least total amount of time the
passenger must spend between flights if all flights keep to their schedules?
(A) 25 min
(B) 1 hr 5 min
(C) 1 hr 15 min
(D) 2 hr 20 min
(E) 3 hr 40 min

看不太懂题目是什么意思啊,有人知道吗?

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哦,谢谢!答案好像就是1小时5分,现在理解了,原来线路是固定的,A->B->C,刚开始还以为要算哪种方案最省时间。有点晕了.

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从A 8:00 出发,2小时30 后到B,到B 时10:30,B站火车8点开始每20分钟一班,所以要等10分钟, 搭10:40从B出发,1(1/6)小时后到C,到C 时11:50,C站火车8:45开始每1小时一般,所以要等55分钟,搭上12:45, 故,总共的等待时间为10+55=65 分钟。答案是B.

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应该是说一个乘客需要做三次飞机分别从A/B/C三个机场出发,A机场的航班8点开始每小时一班,A到B2.5小时;B机场的航班8点开始二十分钟一班,B到C1又1/6小时;C机场的航班8点45分开始每小时一班。问这位乘客需要在航班中转之间最少等待时间。我算出来是B,不知道对不对??

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