math jj 203

luckyhaohuan

203.   DS题，26的divider为k，然后他的remainder是k-2，问是否能确定k的值？
1、k>5
2、k<10
why c?.. should it be b?
since K could only be 1,14,28 (k-2>=0, so k shouldn't be 1).
from 2, k=2

lavenderwu

how about 4 and 7?

luckyhaohuan

u r right, so 5<k<10, pick 7. should be c..

luckyhaohuan

谢谢。