72. The following appeared as part of a recommendation from the business manager of a department store.
“Local clothing stores reported that their profits decreased, on average, for the three-month period between August 1 and October 31. Stores that sell products for the home reported that, on average, their profits increased during this same period. Clearly, consumers are choosing to buy products for their homes instead of clothing. To take advantage of this trend, we should reduce the size of our clothing departments and enlarge our home furnishings and household products departments.”（貌似本月没出过，好写。）
27。公司长期成功取决于员工满意度和安全感。（本月高频）
语文;
GWD原体
Elk now live almost solely in the Rocky Mountains, which would make it seem that elk are mountain dwellers, while they once ranged over virtually all of the continental United States except for a small strip in the extreme Southwest. B
- Elk now live almost solely in the Rocky Mountains, which would make it seem that elk are mountain dwellers, while
- The fact that elk now live almost solely in the Rocky Mountains would make it seem that they are mountain dwellers, but
- It would seem that elk would be mountain dwellers because of their living now solely almost in the Rocky Mountains, but still
- Now living almost solely in the Rocky Mountains, it would seem that elk were mountain dwellers, although
- It seems that elk would be mountain dwellers from the fact that they now live solely almost in the Rocky Mountains, since
还考了 regards as用法
the first of 修辞现行词，谓动的单复数
逻辑只考到了火车换列车，午睡有助记忆。
阅读都是jj的。
数学，
13少，莫怕。没有新的。
我大概遇到了10道jj。 其他简单，大家都会做。
有几道有简易解法，附下：
38 版本1：f(2)=1, f(n+1)=f(n)+n, 求f(20)
版本2：PS 给G代表的函数下了个定义,给了个表达式，问G（20）最后算的时候是一个19+18+17+...+1得等差数列的和
helen2009:
f(2)=f(1)+1 ->f(1)=0
f(3)=f(2)+2 ->f(3)=3
f(4)=f(3)+3 ->f(4)=6
f(5)=f(4)+4=10
f(6)=f(5)+5=15
其实f(n)就是从0加到n-1的和 0 1 3 6 10 15 之间间隔是1，2，3，4，5
f(20)=从1加到19的和=(1+19)*19/2=190
Hang13:确认
偶解
f(20)-f(19)=19
f(19)-f(18)=18
f(18)-f(17)=17
…
f(3)-f(2)=2
f(2)-f(1)=1
等式两边分别相加,左边为f(20)-f(1),右边=19+18+17+…1=19(19+1)/2=190
217
DS题， 有credit card的占总人数的35%-40%， 问既有credit card 又有另外一样什么东西（暂且叫A好了= =）的人数是否占拥有credit card的人数的1/2以上
a, 拥有A的占总人数的70%-75%
b, 既有credit card又有A的人数占拥有A的人数的40%-45%（45%有点不确定。。。）
scarlett826选的C
蓝色回忆：由1：举两个例子吧。
Eg1 0.4有card，0.7有A，0.1都有，没人什么都没有。于是所求比例是0.1/0.4=1/4<1/2
Eg2 0.4有card，0.7有A，0.4都有，0.3都没。于是所求比例是0.4/0.4=1>1/2
所以1推不出
由2：还是举例吧。
Eg1 0.4有card，0.5有A，0.2both，0.3neither。所求为0.2/0.4=1/2
Eg2 0.35有card，0.5有A，0.2both，0.35neither。所求为0.2/0.35<1/2
2也推不出。
1+2：
有card和A的人占总人数的：0.4*0.7~0.45*0.75即0.28-0.3375
所以有both的占有card的人数范围：0.28/0.4-0.3375/0.35即0.7-0.96 确保超过1/2
所以C
偶解：根据条件只要2者兼有占总的超过20%就可以满足。由2可知，2者兼有的至少为40%*70%=28%〉20%。 选C。
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