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GWD6-Q11

怎么没有人讨论这一道题,为什么选D, 不选E


Further-

more, the daily movements of sloth


(20)
bears and American black bears—


which are similar in size to sloth bears


and have similar-sized home ranges—

reveal similar travel rates and distances,

suggesting that if black bear cubs are


(25)
able to keep up with their mother, so

too should sloth bear cubs.

Q 11. Which of the following, if true, would most weaken the author’s argument in lines 18-26 (“Furthermore … sloth bear cubs”)?

              

    A       Cub-carrying behavior has been observed in many non-myrmecophagous mammals.
    B       Many of the largest myrmecophagous mammals do not typically exhibit cub-carrying behavior.
    C      Some sloth bears have home ranges that are smaller in size than the average home ranges of black bears.
    D     The locomotion of black bears is significantly more efficient than the locomotion of sloth bears.

E       The habitat of black bears consists of terrain that is significantly more varied than that of the habitat of sloth bears.
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I am also selecting E, but now think D is better.

Reason: pls notice "furthmore",which is following by "However". So these two examples are to oppose "one explanation is that.....since myrmecophagy entails a low metaboic rate and high energy expenditure....". Therefore, if locomotion of black bears is more efficient, the conclusion will be weakened.

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我觉得上面是解释了D怎么对,说的很有道理
我来说说E为什么错

E:文中说Sloth Bear(SB)和Black bear(BB) 的size 和home range相同,因此BB能做到的(即black bear cubs are able to keep up with their mother)SB也能做到
本选项给出了SB和BB的一个差异,就是BB的栖息地地形比SB的栖息地复杂,那么可以推断BB能做到的(即black bear cubs are able to keep up with their mother)SB更能能做到
所以E实际上是support而不是weaken

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我觉得楼上讲错了

BB和SB的range之类的一样   但地形更复杂   所以会更消耗能量  SB不一定能做到   而且假设SB能做到  那么他的range应该在复杂的地形下比BB小

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