2.An insurance company has a paper record and an electronic record for every claim. For an inaccurate paper record, 60% chances that the electronic record is inaccurate. For an inaccurate electronic record, 75% chances that the paper record is inaccurate. 3% of all the claims are inaccurate both in paper record and in electronic record. Pick one claim randomly, what are the chances that it is both accurate in paper record and in electronic record?
A.97% B.94% C.68% D.65% E.35%
【确定】B 94%,
I've consulted my econometrics instructor , she couldn't get it out either...
I always find difficulity dealing with the % problem..so ,pls help
Thx ^^
For an inaccurate paper record, 60% chances that the electronic record is inaccurate.
x * 60% = 3% x = 5% (inaccurate paper record)
For an inaccurate electronic record, 75% chances that the paper record is inaccurate.
y * 75% = 3% y = 4% (inaccurate electronic record)
=> 2% inaccurate paper record, accurate electronic record
=> 1% inaccurate electronic record, accurate paper record
inaccurate paper record + inaccurate electronic record = 6%
ans:94%
Thank you so much for your elaborate and excelent explain ^^
but I am afraid I will be dizzy dealing with the real test...
so can I think though this way ...
in 100 claim that is inaccurate in paper record , 60 are also inaccurate in electronic record
in 100 claim that is inaccurate in electronice record , 75 are also inaccurate in paper record
and in these 200 claims, 6 are both inaccrate in paper and electronic records ...
so ....but my idea block here ...can not go on ..and also not sure if it is the way out...
