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3. x has 10 choices, y has 11 choices. p and r must have the same x, p and q must have the same y, then
p(11,1)*p(10,1)*p(10,1)*p(9,1)=9900 (r,p de y zuobiao)*(q de y zuobiao)*(r de x zuobiao)*(p,q de x zuobiao)
understanding?
1. it seems something wrong with your problem or your answer
(1). 5^(k-1)>3000==>(5^k)/5>3000===>5^k>15000
(2). 5(k-1)=5^k-500===>how can we draw the answer?
it seems the answer should be A
Pls check the question |
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