求助：一道数学题

longxiaomeim

A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traverling in the same direction and in the same path at a constant rate of 20 miles per hour .The cyclist stops to wait to for the hiker 5 minutes after passing her ,while the hiker continues to walk at her constant rate .How many minutes must the cyclist wait until the hiker catches up?

多谢！

sammen

没明白题意,好像没办法求啊?楼主这是原题,还是JJ啊?

hopr999

（20－4）×5/4＝20

longxiaomeim

能否解释一下，我每次算都是5/4。 多谢！！

jojof5460

自行车们前进的同时，hiker也在行走啊。所以是（20－4）×5是5minutes 产生的distance。clear？