Let me try it.............. (1) x is a multiple of 6 & 9; i.e., x is a multiple of 18; i.e., x = 18m & y = 14n (since y is a multiple of 14) i.e., xy = 252mn or 252k (m,n,k are any positive integers) For k =1, 2, 3, 4 etc; xy is not a multiple of 105 Whereas for k=5, xy is a multiple of 105 ---> INSUFF (2) y is a multiple of 14 & 25; i.e., y is a multiple of 350; [14×25 i.e., x = 6m & y = 350n (since x is a multiple of 6) i.e., xy = 2100mn or 2100k (m,n,k are any positive integers) 2100 is divisible by 105 ... hence xy is a multiple of 105 ... SUFFICIENT Answer is B. |