Q22: If x is negative, is x < -3? (1) x2 > 9 (2) x3 < -9 1) x^2 > 9, then |x| > 3 => x < -3 if x < 0, x > 3 if x > 0, since we already know x < 0, then x < -3, thus 1) by itself is sufficient 2) x^3 < -9, x < -(9)^(1/3), since 3 > 9^(1/3) => -3 < -9^(1/3), x < -9^(1/3) is not sufficient to establish that x < -3, thus 2) by itself is not sufficient Therefore, the answer is A 呵呵,我刚起来的说 |