一道数学题，一直不知道怎么做。求方法

waytousff

10的50次方 – 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer? A.  424 B.  433       C. 440 D. 449 E. 467 完全不懂意思？？求指导

waytouing

10^50-74=999,xxx,xxx,926. sum of the digits in This

integer=9*48+2+6=440.

waytousff

谢谢大神指点，真的是做题做傻了

dreadpower

10^50-74=999,xxx,xxx,926. sum of the digits in This

integer=9*48+2+6=440.
waytouing 发表于 2013-6-4 20:40

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