justag

I think so.

Either..or... [(9*1*8)+(9*8*1)]/(10*9*8)=1/5,
Neither...nor...1-1/5=4/5

Or think like this: Neither S nor T nor P with p=9*8*7/10*9*8=7/10 or Neither S nor T but P with p=(1*9*8)/(10*9*8)=1/10. In sum, 4/5

So, Haryy can be either S or T with p=1/5; neithor S nor T with p=4/5