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507. sorry should be 5. According to context, 7 for each since equal number and total number of 21, First, 1 each color for each group.then go blue color, green , ans the last to distribute red.
R R R 9-3=6
B B B 7-3=4
G G G 5-3=2
4B 2G+2R (6-2)R
Total
7 7 7
So, the number of maximum red = ( 6-2)+1=5
509. Method: 50^2*3 + Pai*1/2*(50/2)^2*3*4 = 3750pi+7500 --> C
510. Are u sure? My way goes like this:
(2) x, 2x, 3*2x if 3*2x=2 --> x=1/3
Can u check it again? thanks! |
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