一社区有45户, 订报纸, 有 R, S, T 三种报,给出了三种报的订户人数分别是, S1=28, S2=17, S3=12,then, subscribe, both R&S, b1=9, both S&T b2=8, both R&T b3=7; Now 给出了一个重要条件, 订了三种的和什么都没有订的人,一样. 然后说, at least subscribe one kind of newspaper,29.
问: Subscribe only one kind Newspaper 的人数 X=?
我的解法: 设三种报都订了的人为: a , a=45-29
X= S1+S2+S3-b1-b2-b3+a
但是, 本本的我在考试的时候, 是 -a, 55555~~~!
希望大家注意. 也欢迎其他网友补充更正. 因为对数字 not for sure, so 以字母代替, 以说明解法.
I think math JJ is very useful. Gmat math is more difficult than that in GRE. JJ is very good to study, practise and take exam. The other books on Gmat Math are easier than what in exam.
AWA
AI: Governments regulating businesses and other organazations,....
AA: Public High School with 200 course, and a private school with 80 courses,...
我的第一篇长文, 在3-6 题. 文章不难理解, 但问题的答案, 不好选. 我大概都作错了. 后来给我的题特别简单. 我越做 depressed. so, just cancle the score.
I believe there is not a short cut for study, I should study harder. I only prepare for GMAT three weeks, thinking I'm already in US studying for three years, should enough for me, but I was wrong. I really admire those students who are still in China, and study so
hard. You will get whatever you want through your hard working.
Good luck for your exam!作者: maryland 时间: 2003-5-1 18:53 标题: [转帖]更正：一道蛮搞的数学JJ--- 订报问题
benben 2003-04-30 11:43:52
一社区有45户, 订报纸, 有 R, S, T 三种报,给出了三种报的订户人数分别是, S1=28, S2=17, S3=12,
then, subscribe, both R&S, b1=9, both S&T b2=8, both R&T b3=7; Now 给出了一个重要条件, 订了三种的和
什么都没有订的人,一样. 然后说, at least subscribe one kind of newspaper, 29.
问: Subscribe only one kind Newspaper 的人数 X=?
我的解法: 设三种报都订了的人为: a , a=45-29=16， X=29-b1-b2-b3+2a
if use S1,S2, S3, then X=S1+S2+S3-2b1-2b2-2b3+4a
欢迎大家讨论。作者: oddyuibe 时间: 2003-5-1 20:29
一社区有45户, 订报纸, 有 R, S, T 三种报,给出了三种报的订户人数分别是, S1=28, S2=17, S3=12,then, subscribe, both R&S, b1=9, both S&T b2=8, both R&T b3=7; Now 给出了一个重要条件, 订了三种的和什么都没有订的人,一样. 然后说, at least subscribe one kind of newspaper,29.
问: Subscribe only one kind Newspaper 的人数 X=?
我觉得是：X=S1+S2+S3-2B1-2B2-2B3+3a, 其中a是三种报纸都订了的户数
from S1, we should subtract those who subscribe S or T, thus S1-B1-B3, however in this process, one more "a" is subtracted, so we should add "a" afterwards: S1-B1-B3+a
similarly, from S2, we subtract those who subscribe T or R, and add the "a" which we unnecessarily subtract, thus S2-B1-B2+a
accordingly, the third one is: S3-B2-B3+a
so, the answer is S1+S2+S3-2B1-2B2-2B3+3a
If you draw venn diagram, the relationship will be very clear.
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