Board logo

标题: 请问思路 [打印本页]

作者: qiqi    时间: 2003-3-11 16:01     标题: 请问思路

7根绳子,MEAN=68,MEDIAN=84,最长的是最短的的四倍再加14,问最长的长度范围,[em12]
作者: tongxun    时间: 2003-3-11 19:21

84-134
a1、a2、a3、a4、a5、a6、a7
a4=84
a5=a6=a7=a4=84

a5=a6=a4=84;a1=a2=a3 =》134
作者: qiqi    时间: 2003-3-12 14:13

多谢!明白
作者: cranberry    时间: 2003-3-12 19:47

请老大详细解释一下,拜托
作者: likerock    时间: 2003-3-13 07:12

My answer is that the longest is between 70 and 134.

Assume the order is a1, a2, a3, a4, a5, a6, a7.  We know a4 is 84.  We also know a7=4*a1+14.  The largest number a7 could have is when the other numbers are the possible lowest, which means a2, a3 = a1 and a5, a6 = 84.  Same reason, the smallest number a7 could have is when the other numbers are the possible biggest, which means a2, a3 = 84 and a5, a6 = a7.  Since we know mean is 68, so the sum is 476.  We can get following equations.

1.  3*a1 + 84*3 + a7 = 476 for biggest number
2. a1 + 84*3 + 3*a7 = 476 for smallest number
3. a7 = 4*a1 + 14 (this is we already know)

from above we can calculate that the a7 is between 70 and 134.

Hope it helps.
作者: qiqi    时间: 2003-3-13 14:50

likerock,最长的长度最小值不可能是70,最长值是70的话,中数怎么可能是84,因为中数的定义是按大小排列的。
作者: likerock    时间: 2003-3-14 00:56

Oops, you're right, qiqi.  I forget another hidden premise a7 >= 84.  Thanks for correcting me.
作者: cranberry    时间: 2003-3-14 23:03

thank you ,guys




欢迎光临 国际顶尖MBA申请交流平台--TOPWAY MBA (http://forum.topway.org/) Powered by Discuz! 7.2