Sorry I have to write in English, not because I like it, but my chinese keyboard does not work and I cannot figure out what's wrong. Anyway I have these 2 urgent questions from the 2002.12.09-2002.12.15
Aand B overlaps by 2
C overlaps A by 3, and C overlaps B by 5
So I thought at least only 2 passes.
What is the correct method to calculate (AnB) given the question (or (BnC) or (AnC) for that matter)?
For example if say a question ask: There are a total of 200 household, with or without TV or phone or both or none. Given 60% have TV (T), and 70% have phone (P), what is (TnP), what is (Not T n Not P)?
Thanks a lot!作者: kitten369 时间: 2002-12-25 01:03
for 100)
I don't think the answer is right. my answer is 0.
Because If we guess everyone in this class pass 2 exam, then there will be 30*2 in total, then 60> 15+17+18 so at least 0 pass.
in other word, A and B overlaps by 2, then for the member in C, they distribute into the 30-2 (which only pass 1 exam) so there will on one pass
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