X ,Y and Z each try independently to solve a problem .If their individual probabolity for success are ¼,1/2 and 5/8 ,respectively, what is the probabolity that X and Y ,but not Z ,will solve the problem.
(a) 11/8 (b) 7/8 (c) 9/64(d)5/64(e)3/64
answer (e)
能不能帮忙解释一下。为何是1/4x1/2x3/8=3/64 没有解题的思路。谢谢其实这题和抛3次硬币的题有点类似,不同的只是每次的正反概率不同了.
X,Y参加,所以取他们的正概率即成功的概率,Z不参加,所以取他的非正概率,即1-5/8=3/8, 3者乘之即得.
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