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标题: [求助] [打印本页]

作者: 吴大伟 时间: 2002-12-3 15:09 标题: [求助]

XDJM - can you help explain ?

502.K的4次方被32除remainder为0. what is the possible remainder for K divided by 32.
I 2, II 4, III 6.
[确认]4

Thanks in advance[em18]

作者: 春暖花开 时间: 2002-12-3 15:32

K的4次方被32除remainder为0, 则K^4＝32A=2^5A
即K^4中至少含5个2，I, III代入均不满足条件，选II

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