标题:
one math JJ
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作者:
lindafirst
时间:
2002-11-30 20:13
标题:
one math JJ
一个12个数的集合,最小的数是-4,后一项比前一项大1,问正整数的range
ANSWER: 11
why? how to solve it?
thank you
作者:
猫猫头
时间:
2002-11-30 21:59
最小是4,每个比前一个大一,所以最大的是-4+11+7==>range=7-(-4)=11
作者:
freedim
时间:
2002-12-1 03:10
我有个问题,题目问的是集合中正整数的range,谁个讲的11
作者:
lisaislisa
时间:
2002-12-1 09:07
still can't get it out , kitten
-4+11=7 but it's asking for the range of +N , isn't it ?
^^
thx!
作者:
daydream
时间:
2002-12-1 10:33
The answer should be 7-1 = 6 .
作者:
lisaislisa
时间:
2002-12-1 10:54
7-1? ! why ?
ok all of the numbers are as follows
-4 -3 -2 -1 0 1 2 3 4 5 6 7
and then the range for +N is 7
isn't it ?
confussing.....
作者:
tongxun
时间:
2002-12-1 20:15
7-(-4)=7+4=11
作者:
freedim
时间:
2002-12-1 20:24
正整数?
作者:
tongxun
时间:
2002-12-1 20:45
freedim:你对。我将条件给忘了。7-1=6。谢谢你的提醒!
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