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标题: 问一个GWD的题 [打印本页]

作者: zhangxirui02    时间: 2006-7-4 06:44     标题: 问一个GWD的题

Q32:

What is the remainder when the positive integer x is divided by 8?

(1)     When x is divided by 12, the remainder is 5.

(2)     When x is divided by 18, the remainder is 11.

                  

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.

答案是E,我猜对了

但是那位NN能跟我讲讲解答过程么?万分感谢拉!!!!


作者: xiaoyue    时间: 2006-7-4 13:12

通项问题一招搞定

看到过一堆堆问通项如何求的帖子啦,这里说一个一招搞定的做法:

通项S,形式设为S=Am+B,一个乘法因式加一个常量

系数A必为两小通项因式系数的最小公倍数

常量B应该是两个小通项相等时的最小数,也就是最小值的S

例题:4-JJ78(三月84).ds某数除7余3,除4余2,求值。

解:设通项S=Am+B。由题目可知,必同时满足S=7a+3=4b+2

A同时可被7和4整除,为28(若是S=6a+3=4b+2,则A=12)

B为7a+3=4b+2的最小值,为10(a=1.b=2时,S有最小值10)

所以S=28m+10

满足这两个条件得出的通项公式,必定同时满足两个小通项。如果不能理解的话,就记住这个方法吧,此类的求通项的问题就能全部,一招搞定啦






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