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标题: GWD1-Q28 [打印本页]

作者: invisiblewys    时间: 2005-12-30 07:43     标题: GWD1-Q28

Q28:

Three printing presses, R, S, and T, working together at their respective constant rates, can do a certain printing job in 4 hours. S and T, working together at their respective constant rates, can do the same job in 5 hours. How many hours would it take R, working alone at its constant rate, to do the same job?

A. 8

B. 10

C. 12

D. 15

E. 20

大家如下的方法是怎么得出的呢???看不懂啊

1/4 - 1/5=1/20

所以=1/(1/20)=20小时。


作者: LHL888    时间: 2005-12-30 20:16

这种工作效率问题不是有普遍办法么?一步一步来就好了,花不了多少时间。

设R,S and T为工作效率,也就是每小时能做总工作的多少

设(S + T) = X ,反正分开没意义。用 总工作量/效率 = 时间 来列方程

1/(R+X)=4

1/(X)=5

求得R=1/20


作者: invisiblewys    时间: 2005-12-31 07:35

明白了。谢谢!!!




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