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标题: 七宗罪 [打印本页]

作者: della    时间: 2002-10-29 22:09     标题: 七宗罪

听说有AWA七宗罪这中好东东。遍寻不着不知哪能找到。谢谢!
作者: 猫猫头    时间: 2002-10-29 22:26

我把它打印出来了
不过我觉得一般般
让我找找哦,你别急~~
作者: 猫猫头    时间: 2002-10-29 22:28

找到了 第一宗罪:无因果联系 The author commits a fallacy of causal oversimplification. The line of the reasoning is that because A occurred before B, the former event is responsible for the latter. (The author uses the positive correlation between A and B to establish causality. However, the fact that A coincides with B does not necessarily prove that A caused B.) But this is fallacious reasoning unless other possible causal explanations have been considered and ruled out. For example, perhaps C is the cause of these events or perhaps B is caused by D. 第二宗罪 Insufficient-sample The evidence the author provides is insufficient to support the conclusion drawn from it. One example is logically unsounded to establish a general conclusion (The statistics from only a few recent years are not necessarily a good indicator of future trends), unless it can be shown that A1 is representative of all A. It is possible that.... In fact, in face of such limited evidence, the conclusion that B is completely unwarranted. 第三宗罪: 错误类比 (based on a false analogy )<横向> The argument rests on the assumption that A is analogous to B in all respects. This assumption is weak, since although there are points of comparison between A and B, there is much dissimilarity as well. For example, A..., however, B.... Thus, it is likely much more difficult for B to do.... 第四宗罪 all things are equal<纵向> The author commits the fallacy of “all things are equal”. The fact that happened two years ago is not a sound evidence to draw a conclusion that.... The author assumes without justification that the background conditions have remained the same at different times or at different locations. However, it is not clear in this argument whether the current conditions at AA are the same as they used to be two years ago. Thus it is impossible to conclude that.... 第五宗罪 Either-Or choice The author assumes that AA and BB are mutually exclusive alternatives and there is no room for a middle ground. However, the author provides no reason for imposing an either-or choice. Common sense tells us that adjusting both AA and BB might produce better results. 第六宗罪 survey is doubtful The poll cited by the author is too vague to be informative. The claim does not indicate who conducted the poll, who responded, or when, where and how the poll was conducted. (Lacking information about the number of people surveyed and the number of respondents, it is impossible to access the validity of the results. For example, if 200 persons were surveyed but only 2 responded, the conclusion that...would be highly suspect. Because the argument offers no evidence that would rule out this kind of interpretations,) Until these questions are answered, the results of the survey are worthless as evidence for the conclusion. 第七宗罪 gratuitous assumption The author falsely depends on gratuitous assumption that.... However, no evidence is stated in the argument to support this assumption. In fact, this is not necessarily the case. For example, it is more likely that.... Therefore, this argument is unwarranted without ruling out such possibility.
作者: della    时间: 2002-10-29 22:54     标题: 谢谢猫猫头! 又有问题如下:

6个球,号码1到6,取出一个又放回去再取第二个.SUM是8.问其中有一个是5的概率.
(OLD JJ)
2/5

我不会做.
2+6,3+5, 4+4 只有这三种情况和为8. 如何推出2/5? 不是 1/3吗?

另:两个班中数平均数, 求合并后的中数平均数. 这样的问题都是选E吗?

谢谢!
作者: 猫猫头    时间: 2002-10-29 22:57

2+6
6+2
3+5
5+3
4+4
作者: della    时间: 2002-10-29 23:00     标题: 谢谢! 中数平均数的问题如何解决呢?

中数平均数的问题如何解决呢?
作者: 猫猫头    时间: 2002-10-29 23:09

你要猫猫头跟你上课课吗?
哈哈~~
具体点问好吗?
平均数就是把总数/数目
中数,如果是单数的,就是中间那个;如果是双数的,就是中间两个的平均指
作者: della    时间: 2002-10-29 23:43     标题: 老JJ

不好意思. 我指的是一道老JJ. 已知两个班中数平均数, 求两个班合并后的中数平均数好象都说选E. 不知如何解.
作者: 猫猫头    时间: 2002-10-29 23:48

这个只能算个大致的
因为具体的无法算出来
作者: tongxun    时间: 2002-10-29 23:54

della:
先将每个班的中数求出,这样就可以知道那个班至少有多少人的分数是大于等于多少了。
将两个班级合起来,我们可以利用两个班级的中数求出至少有多少人的分数大于等于多少。
比如:A班有11个人,中数是50分。咱们可以知道在这个班级里,至少有6个人的分数大于等于50分。
B班有21人,中数是70分,则至少有11人的分数大于等于70分。
两个班级和起来,咱们知道A+B中至少有17人的分数大雨等于50分。
就这么算
作者: della    时间: 2002-10-30 16:55     标题: 中数平均数具体问题

具体题目如下:DS题
       中数   平均分数
A班     80      82
B班     78      74
以上是AB两个班考试成绩的中数和平均数,问两个班学生合在一起时其学生考试分数的算数平均直是否大于其中数。
(1)A班有37人,B班有40人
(2)A和两个班工人

按照你的思路, A班有19人大于等于80分,B班至少有20人(最多21人)大于等于78分。两个班合并后至少有39人大于等于78分,而两个班的平均数是( 82X37 +74X40)除以77人,是77。8分  所以78>77.8 中数大于平均数。 A是充分的。

但好象考完的人都说这题选 E 。 清问我算的对吗?
作者: tongxun    时间: 2002-10-30 17:04

della:你的才是对的。考完的人,他们的机警中的数字肯定变了。就我所知,目前这个题目的数字形式,有3种,其中一个的答案是E、一个是A、一个是B。
作者: della    时间: 2002-10-30 17:11

对不起, 条件2是: A和两个班共77人.

如果数字有变, 选 E 可以理解. 什么条件下会选B呢?
作者: della    时间: 2002-10-30 17:30

看JJ 又看见这道题了. 如果条件顺序变一下就是B 了.;->
还接着上面这道题, 如果所求的平均数是79 这道题就选E 是吧?
作者: tongxun    时间: 2002-10-30 17:44

所求的平均数是79 这道题就选E
条件顺序变一下就是B




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