Five boxes maximum capacity currently hold pieces
90 70
80 70
50 30
80 50
40 40
rearrange it so that the maximum capacity - holding pieces for all five are the same. So second box should be ?
【讨论】62
90-x=80-y=50-z=80-a=40-b=k;
(90-k)+(80-k)+(50-k)+(80-k)+(40-k)=70+70+30+50+40=260;
340-5k=260;
k=16 ; 80-16=64 不是62呀???作者: 猫猫头 时间: 2002-10-24 21:27