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标题: Prep数学题 [打印本页]

作者: jenningsyao    时间: 2011-8-29 06:51     标题: Prep数学题

Sets A, B, and Chave some elements in common.  If 16elements are in both A and B, 17 elements are in both A and C, and 18 elementsare in both B and C, how many elements do all three of the sets A, B, and Chave in common?

(1) Of the 16elements that are in both A and B, 9 elements are also in C.

(2) A has 25elements, B has 30 elements, and C has 35 elements.


条件1是sufficient的,条件2,如果不用列举法,怎样得出sufficient or not?
作者: timothyyung    时间: 2011-8-29 21:12

条件2的 我也很疑惑 乍眼看 感觉答案能斗出来 可实际上是不可以的吧?有没有人来肯定答复一下呢?
我选的D是错的
作者: citidandan    时间: 2011-8-30 06:16

设都相交的是x,则按条件二得:
A16+17-x<25即x>8
B16+18-x<30即x>4
C17+18-x<35即x>0
无法求得x




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