标题: 求助--费费逻辑94 [打印本页]
作者: chchencheng 时间: 2011-8-11 06:51 标题: 求助--费费逻辑94
94. When 100 people who have not used cocaine are tested for cocaine use, on average only 5 will test positive. By contrast, of every 100 people who have used cocaine 99 will test positive. Thus, when a randomly chosen group of people is tested for cocaine use, the vast people is tested for cocaine use, the vast majority of those who test positive will be people who have used cocaine.
A reasoning error in the argument is that the argument
(A) attempts to infer a value judgement from purely factual premises
(B) attributes to every member of the population the properties of the average member of the population
(C) fails to take into account what proportion of the population have used cocaine
(D) ignores the fact that some cocaine users do not test positive
(E) advocates testing people for cocaine use when there is no reason to suspect that they have used cocaine
正确答案是C)可是怎么也和题目挂不上钩。私下盼望D)如果是ignores the fact that some people test positive even they never used cocaine 那我就毫不犹豫地选它。可惜不是。这道题该怎么考虑请指教。
作者: haoye12321 时间: 2011-8-12 06:21
虽然没用过cocaine的人5%positive,用过的人99%positive.
但是注意，对整个随机人群（含有两类人：用过的和没用过的）进行测试时，应注意这两类人的比例。eg:如果用过的占整人群1%，而没用过的占99%，即使前者positive的人比例为0，后者positive的比例为100%,总体中positive的人也不过是1%。
D选项是个作用不确定选项，因为有一些测试错误，不一定会导致结论不成立。上面这个例子也可以证明这一点。
作者: chchencheng 时间: 2011-8-12 19:54
谢谢你
看了你的解释,觉得好像明白了,可是脑袋里的结还是没能全解开。后天考试了,希望运气好,不要到时大脑停止运作。
作者: xyxxyxxyx 时间: 2011-8-16 06:18
"Thus, when a randomly chosen group of people is tested for cocaine use, the vast people is tested for cocaine use, the vast majority of those who test positive will be people who have used cocaine. "
这句话是结论，结论认为：一个随机测试，如果绝大多数人的cocaine最后检测结果是阳性，则这些人一定是使用了cocaine的那部分人。但是argument里少考虑了一个问题：打个比方，100个人里，如果没有服用cocaine的人，占样本人群的99%，那么最终这些没有服用cocaine但是还是结果呈阳性的人，为4个人；而剩下的1%，即1个人，这1个人的99%是服用了cocaine并且结果呈现阳性的人，即0个人。这样子的话，绝大多数实验结果为阳性的人群则是那些没有服用cocaine的人咯~~~
所以C是对的：作者没有考虑到，那些真正服用了cocaine的人们，占总人群的人数
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