标题: [求助]--分球问题 [打印本页] 作者: vancouver 时间: 2002-10-22 05:02 标题: [求助]--分球问题
Five boxes maximum capacity currently hold pieces
90 70
80 70
50 30
80 50
40 40
rearrange it so that the maximum capacity - holding pieces for all five are the same. So second box should be ?
答案肯定对,但题干的数字有出入。ANSWER: 62作者: smilingme 时间: 2002-10-22 08:09
好像答案部队,是64来着作者: vancouver 时间: 2002-10-22 12:10
How can I resolve this problem? Your help is really appreciated.作者: yiyaya 时间: 2002-10-22 12:23
who can give me the detail in solving this problem?作者: vancouver 时间: 2002-10-22 13:40 标题: [讨论]
I am not quite sure if the following way is the correct solution.
(70+70+30+50+40) /(90+80+50+80+40) = 13/17
80*(13/17)=61.2作者: smilingme 时间: 2002-10-22 15:23
看来这道题跟我挺过得去的,我随便挑了一个贴子,就是啦!大家眼睛睁大咯:
2、
Five boxes maximum capacity currently hold pieces
90 70
80 70
50 30
80 50
40 40
rearrange it so that the maximum capacity - holding pieces for all five are the same. So second box should be ? (62)
-------------------------------
62
先将多的挑出来。平均分:(20+10+20+30+0)/5=16
这时的各个盒子的差就是16。
第二个盒子:80-16=62作者: Kilroy 时间: 2002-10-22 20:07