1,For every positive even integer n, the function h(n) is defined to be the product of all the even integers from 2 to n, inclusive. If p is the smallest prime factor of h(100)+1, then p is
1) between 2 and 10
2)between 10 and 20
3)between 20 and 30
4)between 30 and 40
5)greater than 40
Answer is 5)greater than 40作者: abixiaoxinyue 时间: 2011-2-12 07:34
This one has been explained before.
Basically,
1) These consecutive natural numbers h(100) and [h(100) + 1] are co-prime, meaning that they do not share any prime numbers as their cofactors.
2) h(100) contains all the prime numbers between 2 (from 2) and 47 (from 94).
3) Then prime numbers among factors of [h(100) + 1] would not include any prime numbers between 2 and 47.
4) Then the smallest prime facotr of [h(100) + 1] is bigger than 47.作者: avalon9527 时间: 2011-2-12 07:48
Hey thank you so much! I got it right now. Really appreciate your answer.作者: xiexiang 时间: 2011-2-13 06:54
2) h(100) contains all the prime numbers between 2 (from 2) and 47 (from 94).
请问,这一步有些不理解,原文不是说 h(100)是 product of 2 to n 吗?
谢谢作者: abixiaoxinyue 时间: 2011-2-14 20:45
2, 4, 6, 8, 10, 12, 14, 16, 18, . . . 92, 94, 96, 98, 100
is the same as
2, 2*2, 2*3, 2*4, 2*5, 2*6, 2*7, 2*8, 2*9, . . . 2*46, 2*47, 2*48, 2*49, 2*50
So the product of the second series contains factors of 2 and 2, 3, 4 ,5, 6, 7, 8, 9, . . . 46, 47, 48, 49, 50.
47 is the biggest factor of h(100), which is a prime number.作者: pangpangshin 时间: 2011-2-15 06:53
Thanks for the answer~~
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