According to the formula:
the number of factor of (a^x*b^y*c^z),where a,b,c are different prime factors,=(x+1)(y+1)(z+1)
Of course,a,b,c and x,y,z can expend to c,d,e…… to meet the different questions.作者: xiruihuang 时间: 2010-5-29 22:20
It is not form OG but from what we have learned from math teather in high school.The validity of this fomula is guaranteed.You can put some values to test it.作者: xiruihuang 时间: 2010-5-30 22:19