A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and
each participant is to receive a different code?A. 4
B. 5
C. 6
D. 7
E. 8
我看了讨论,但是看不懂啊,请大牛解释一下啊。A B C D E.....中选1个或2个排12个不同的号码。最少需要几个字母
如果用4个字母,P(4,2)/2+p(4,1)=10不够
5个字母。P(5,2)/2+p(5,1)=10+5=15.
可以验证一下: 4个字母时:A. B . C .D. AB. AC. AD. BC. BD. CD
5个字母:A. B. C . D. E. AB. AC AD AE BC BD BE CD CE DE (记住要按字母前后顺序,和只选1和2个)
x+x(x-1)/2>12,求出是要大于5。之所以要除以2是in alphabetical order,呵呵,我自己做的时候没注意,汗啊。
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