Board logo

标题: GMAT Pre Math 题求助!! [打印本页]

作者: Snazzy    时间: 2009-3-11 08:28     标题: GMAT Pre Math 题求助!!

Q28:

Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day.  If r percent of the store’s revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper B, which of the following expresses r in terms of p?

A.    100p / (125 – p)

B.     150p / (250 – p)

C.     300p / (375 – p)

D.    400p / (500 – p)

E.     500p / (625 – p)

Thank you


作者: karen_gao    时间: 2009-3-11 16:11

假设该店卖出Newspaper A的数量为A,卖出newspaper B的数量为B,则有:

r%(A+1.25B)=A,

P%(A+B)=B;

然后应该就可以得出答案了,我就不具体算了。


作者: hebbechou    时间: 2009-3-11 17:03

题目的意思是"上周日某商店卖报纸.A报每份卖1元,B报每份卖1.25元.除此以外,没有卖别的报纸.如果百分之R的营业额来自于卖A报所得,B报卖出的份额占到百分之P的话,下面哪个能正确的用P表示出R?
作者: emma-maple    时间: 2009-3-12 16:52

假设A报卖出X份,B报迈出Y份,根据条件知道:

R/100=1X/1X+1.25Y

P/100=Y/X+Y

得不出答案啊!


作者: boussoler    时间: 2009-3-13 07:13

我算出来的答案跟选项都对不上。。。
假设卖出去n分,n(1-p)*1.00是a的收入
b的收入是n*p*1.25
我们知道r是a的总收入百分比, 哪么b占1-r
所以,(1-r)/r=n*p*1.25/n(1-p)*1.00
r=(1-p)/(0.25p+1)
cc...结果跟答案相差甚远!
可是我没觉的思路有错误,请指点





欢迎光临 国际顶尖MBA申请交流平台--TOPWAY MBA (http://forum.topway.org/) Powered by Discuz! 7.2