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标题: GMATPrep请大家帮忙 [打印本页]

作者: lansha8uo 时间: 2008-4-2 07:29 标题: GMATPrep请大家帮忙

1. XY+Z=X(Y+Z)

Answer: X=1 or Z=0

But I chose X=1 and Y=1

不是也可以吗?

2.For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the two sequence for which the product of the two consecutive terms is negative. What is the number of variations is in sign for the sequence. 1, -3, 2, 5, -4, -6

Answer:3個

3. For which of the following function f is f(x)=f(1-x)

Answer: f(x)=x^2(1-x)^2

请大家帮帮忙!谢谢

作者: Maggiewjys 时间: 2008-4-2 13:02

我认为a是正确的

total rainfall for the year was 20 percent higher in 1990 than in 1910.

与 the number of days with heavy rainfall was lower 有区别

比如说，heavy rainfall的天数比较少，但是在仅有的几天里面heavy rainfall（即雨量）很大，那么可能造成total rainfall仍然比较高

作者: xihonghui 时间: 2008-4-2 13:05

1. XY+Z=X(Y+Z)

Answer: X=1 or Z=0

But I chose X=1 and Y=1

不是也可以吗?

楼主考虑的不全面.依楼主如果只考虑X为1的情况等式是可以成立的,但是如果仅考虑Y为1等式是不成立的,当Y=1时,等式为X+Z=X(1+Z),显然不成立,实际上还有一种情况Z为0则没有考虑

作者: lingri88 时间: 2008-4-8 06:49

QUOTE:

1. XY+Z=X(Y+Z)

Answer: X=1 or Z=0

But I chose X=1 and Y=1

不是也可以吗?

According to what you've provided, I think your answer should be right.

Answer:3個

I'm not sure about the where does the 'highlighted' two come from.

My understanding is that, the question asks you how many pairs of consecutive terms in the sequence have a negative product.

In the sequence shown, there are three pairs.

Namely, 1&(-3), (-3)&2, 5&(-4)

3. For which of the following function f is f(x)=f(1-x)

Answer: f(x)=x^2(1-x)^2

请大家帮帮忙!谢谢

f(1-x)=(1-x)^2*[1-(1-x)]^2=(1-x)^2*x^2=f(x)

请大家帮帮忙!谢谢

f(1-x)=(1-x)^2*[1-(1-x)]^2=(1-x)^2*x^2=f(x)

作者: peiyangzhe 时间: 2008-4-10 06:56

X=1 and Y=1是X=1 or Z=0的子集，所以后者

作者: acinderellas 时间: 2008-4-10 18:13

f(1-x)=(1-x)^2*[1-(1-x)]^2=(1-x)^2*x^2=f(x) 看不懂啊！

作者: chelseayang 时间: 2008-4-11 06:57

第一题，楼主选的答案包含于X=1 or Z=0之中

第二题，楼主应该大错了个地方，就是sequence前面没two,这题是问相邻两数乘积为负的有几对。选3

第三题，把1-x代入f(x)=x^2(1-x)^2

f(1-x)=(1-x)^2*x^2=x^2(1-x)^2=f(x)满足f(x)=f(1-x)

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