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标题: 几道JJ求助 [打印本页]

作者: gmat2002 时间: 2002-9-18 11:26 标题: 几道JJ求助

1.问X除以2的余数是几？
A）X除以5的余数是奇数
B）X除以10的余数是奇数
?E(because x can be negative, if it is postive the answer will be D)

2.the percentage of the teachers who participate in a
  workshop is 60%, some teachers are teaching arts.
  what is the percentage of those arts teacher among
all people attending workshop?
1)there are 200 people attending
2)among those teachers,there are 72% teacher that don't teach art
?E

3.
there are only cans of peas, carrots, corns in the box,
  how many cans should Sue remove before she get the pea?
1)there are 18 cans of carrots and corns
2)there are totally 24 cans in the box
???

作者: tongxun 时间: 2002-9-18 12:21

1、我认为是B。因为B，已经可以确定该数是奇数，奇数/2，余1。
2、E
3、A。题目应该是how many cans at least吧。

作者: cook 时间: 2002-9-18 14:01

1.D 2.E

作者: tongxun 时间: 2002-9-18 17:31

6/5 余1， 11/5 余1， 6/2 余0，11/2 余1。怎会是D呢？

作者: brigittew 时间: 2002-9-18 18:28

1。E，因为无法确定X的值，1。2两个条件只能得出X是奇数
2。E，1。给出的条件只能得出教师的总人数，2，只能得出不是ART教师的人数，条件并未说明教师都是ART TEACHING 或给出比例，
3。if there is 'at least' or other conditions to limit, answer should be A.

作者: liangsheng2 时间: 2002-9-18 21:01

既然可以确定是奇数，奇数除以2后的余数当然只能是1喽。答案应该是B才对。

作者: cook 时间: 2002-9-19 12:25

Sorry, B, E

作者: gmat2002 时间: 2002-9-20 12:08

as to problem 1
suppose X is positive, e.g 3,5. we can get remainder 1 after dividing 2
suppose X is positive, e.g -3,-5. we can get remainder -1 after dividing 2
therefore. answer should be E

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