If w, x, y, and z are on-negative integers, each less than 3, and w(3^3)+x(3^2)+y(3)+z=34, then w+z=?
A.0 B.1 C.2 D.3 E.4
The answer is C. Can any one tell me how to get this answer?
Thank you.作者: noapple 时间: 2004-2-1 15:53
first, what's mean on-negative?
if w=0, x=3, y=2, z=1 9*3+3*2+1=34
then w+z=1
why the answer is C ?作者: LittleLilyLiAng 时间: 2004-2-3 11:13
我也认为答案是1。
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