If the product of the integers w, x, y, and z is 770, and if 1<w<x<y<z, what is the value
of w+z?
请高手指点如何解答.
770=2*5*7*11
1<w<x<y<z,
so, w=2, x=5, y=7, z=11
w+z=2+11=13
2,5,7,11
w,x,y,z
w+z=2+11=13
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