请教一下这道数学题目，谢谢拉

greattaste

请问一下这道题目怎样解答？

If 10⁵⁰-74 is written as a interger in base 10 notation, what is the sum of the digits in that interger?

A   424

B  433

C  440

D 449

 E 467

 答案是Ｃ　，　请问一下有哪位朋友能够告诉我，这个答案是怎样算出来的呢？谢谢拉

daoying

10⁵⁰-74 =999...99926，其中有48个9，the sum of the digits =48*9+2+6=440

daoying

10⁵⁰-74 =999...99926，其中有48个9，the sum of the digits =48*9+2+6=440