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[求助]天山 4-29

Q29

The toll for crossing a certain bridge is $0.75 each crossing. Drivers who frequently use the bridge may instead purchase a sticker each month for $13 and then pay only $0.3 each crossing during that month. If a particular driver will cross the bridge twice on each of x days next month and will not cross the bridge on any other day, what is the least value of x for which this driver can save money by using the sticker?

A 14

B 15

The answer is B but I think the answer is A

0.75×2 ×N13+0.3×2 ×N

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我的解法是:

(31/x)(2)(0.3)+13 < (31/x)(2)(0.75)

求X的最小值....

可是怎么算不出來啊...

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X如果是相隔的天数的话,最小值应该是1的,我想它应该问的是x的最大值,就是15没错.

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cross the bridge twice on each of x days next month : 在下月,X天中的每一天过桥两次,即为只有X天过桥,因此过桥总次数为 2X,

使用sticker省钱,则其成本必然小于等于没有使用sticker的成本

13+2X * 0.3<=2X * 0.75 解之得:X>=14.4 故最小值为15 答案B

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