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老题新问GWD-8-Q41,至今没有定论:B or C

GWD-8-Q41:

When drive-ins were at the height of their popularity in the late 1950’s, some 4,000 existed in the United States, but today there are less than one-quarter that many.

 

A.      there are less than one-quarter that many

 

B.      there are fewer than one-quarter as many

 

C.      there are fewer than one-quarter of that amount

 

D.      the number is less than one-quarter the amount

 

E.       it is less than one-quarter of that amount

 

B套用了两个比较结构:fewer than, as many(as),可以吗?

 

是否可以根据amount修饰不可数排除C,D,E?

 

到底正确答案是什么?

 

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新PREP2中答案是B fewer 和 as many搭配,以前也讨论过的。

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关于这道题,我有2个问题。1,less是不是只可以修饰不可数,还是都可以修饰。修饰可数是不是只可以用few.

2. amount的用法,是不是可以修饰可数不可数呀啊?谢谢解答。

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我觉得答案是 A

GWD-8-Q41:

When drive-ins were at the height of their popularity in the late 1950’s, some 4,000 existed in the United States, but today there are less than one-quarter that many.

单独修饰分数,用less不用fewer,修饰 分数+of+n,由所修饰的n决定用less还是fewer

修饰可数名词用many,修饰不可数名词用amount。drive-ins是可数名词,所以用amount的全错,排除CDE,剩下AB。

B选项 there are fewer than one-quarter as many

as many结构错误,应该as many as,这是次要,关键在于as放在one-quarter和many之间,不能形成什么的几分之几这种结构。那么fewer应该就近修饰one-quarter,而修饰分数应该用less。

其实答案A之所以对,只要理解less than one-quarter这个结构是一个意群即可,或者理解成1/5,1/6之类的,也是一个分数,less than修饰one-quarter。1/5 that many完全可以理解成分数+of+n这个结构,由可数n决定用fewer不用less

因此这题我认为选A

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