Lists S and T consist of the same number of positive integers. Is the median of the integers in S greater than the average (arithmetic mean) of the integers in T?
(1) The integers in S are consecutive even integers, and the integers in T are consecutive odd integers.
(2) The sum of the integers in S is greater than the sum of the integers in T.
答案给的是C
我选E
举例来看
S={2，4，6} T={1，3，5}，符合条件（1）（2）
S的中位数是4，T的平均数是4.5。此时S的中位数小于T的平均数。
S={4，6，8} T={1，3，5}，符合条件（1）（2）
S的中位数是6，T的平均数是4.5，此时S的中位数大于T的平均数
所以两个条件都不足以得出结论
请问这样想哪里有错误？
谢谢指教 | 
