返回列表 发帖

有道prep上的数学题 不是很明白。

a sum of $20000 from a certain estate was divided among a spouse and 3 children, how much of the estate did the youngest child receive?

1,the spouse receive 1/2 of the sum from the estate, the oldest child receive 1/4 of the remainder.

2. each of the two younger children receive $12500 more than the oldest child, and $62500 less than the spouse.

key:c

问题来了, 题目是问the youngest child 的嘛。但根据条件只能知道the two younger chilldren个人得的钱啊,还是不知道the youngest.....

收藏 分享

题目的数字你确认都对了?a sum of $20000 ,but $62500 less than the spouse?

TOP

噢~不好意思噢  sum是200000; 但是主要的是我想问最后就只能知道2个younger children 得到钱啊 ,还是不能知道他he youngest child 能得到多少钱 啊。

TOP

200000/2=100000(spouse得的钱)

100000/4=25000(oldest得的钱)

剩下200000-100000-25000=75000(2个young得的钱)根据2. each of the two younger children receive $12500 more than the oldest child, and $62500 less than the spouse,说明2个young得的钱是一样的,所以75000/2=37500(每个young得的钱)。LZ没看清2的意思吧。。。

TOP

那2个younger 就不存在the youngest 了吗

TOP

存在是存在的,不过他们2个得到的钱是一样的,这是重点。

TOP

不是2就可以了吗? 应该是B吧[em04]

TOP

如果2 YOUNGER 是一样的钱,那么 2C+(C-12500)+(C+62500)=200000,就可以知道C=37500,答案不就是B?

那么C? 是啥意思

谁来说一下

TOP

返回列表

站长推荐 关闭


美国top10 MBA VIP申请服务

自2003年开始提供 MBA 申请服务以来,保持着90% 以上的成功率,其中Top10 MBA服务成功率更是高达95%


查看