The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale. The argument above is flawed because it fails to take into account - Changes in the population density of both Meadowbrook and Parkdale over the past four years.
- How the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale
- The ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale
- The violent crime rates in Meadowbrook and Parkdale four years ago
How Meadowbrooks’ expenditures for crime prevention over the past four years compare to Parkdale’s expenditures.
这个题目的答案是D，但是因为题目中说的是，两个城市的犯罪增长率，所以即使以前的犯罪率不一样，也不能改变犯罪增长率的差异啊？
所以明显M城市的犯罪增长率比P城市的高，
但是B选项则说M城市的人口增长更快，因为人更多了，所以犯罪率也容易变大了，
请讨论！
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