Q22:

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago.  The corresponding increase for Parkdale is only 10 percent.  These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

The argument above is flawed because it fails to take into account

1. changes in the population density of both Parkdale and Meadowbrook over the past four years

2. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

3. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

4. the violent crime rates in Meadowbrook and Parkdale four years ago

5. how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures

答案是D,为什么不是B呢

这类比例的题目需不需要考虑分母的问题,我一直搞不明白

这道题我的思路是这样的，这个首先是个削弱题，那么我们看题目，题目重视M与P的比较最后得出一个结论说M的居民比P的更易被violent crime伤害。首先如果看过lawyer那个帖子的话就应该立刻联想到这个术语两个比较的题，那么削弱的答案方向一般就是两个东西的本质有区别，这里也就使说M与P的一开始的对比基点不同，于是按照方向找答案D.如果是不能做到这一步的话，那我们来看题，这是写arg也会常出现的错误，只是说了在一段时间内一个比另一个处于优势或劣势，这个是不行的。攻击的方向还有几个，一个就是violent rate in some place不能代表一个地方居民是否就会become victims

Q22:

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago.  The corresponding increase for Parkdale is only 10 percent.  These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

The argument above is flawed because it fails to take into account

1. changes in the population density of both Parkdale and Meadowbrook over the past four years
2. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale
3. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale
4. the violent crime rates in Meadowbrook and Parkdale four years ago
5. how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures

 Answer: D

Meadowbrook is 60 percent higher now

Parkdale is only 10 percent higher now

结论说Meadowbrook的犯罪率更高. 显然有问题

如果M以前的犯罪率是X, 则现在是1.6X

如果P以前的犯罪率是Y, 则现在是1.1Y

结论说1.6X>1.1Y 可是我们并不知道X, Y的大小!

D正确地指出了问题所在